Q1:
0
1
2
3
4
5
6
7
8
9

Q2 there will be one empty line between each lines of numbers like:
1

2

3

4

5

6

7

8

9


Q3 All of them will be outputed in one line, like this:
0 1 2 3 4 5 6 7 8 9 

Q4 when it starts at 1, it will be:
for (int i {1}; i < 10; ++i) {
    cout << i << "\n";
}

and when i starts at 5, it will be:
for (int i {5}; i < 10; ++i) {
    cout << i << "\n";
}

Q5 it's output is:
0
1
2
3
4
5
6
7
8
9
10

this is because when we are setting the forloop, we set it when i <= 10, i++ instead of i < 10, this <= cause i increaseto 10 instead of 9 in previous questions.


Q6 the code will be like this:
for (int i {10}; i <= 20; ++i) {
    cout << i << " ";
}

Q7 this time it will increase 10 at the same time so it will be like:
10
20
30
40
50
60
70
80
90
100
 

Q8
for (int i {2}; i <= 8; i += 2) {
    cout << i << "\n";
}

Q9 the output it like:
10
9
8
7
6
5
4
3
2
1
0

the reason it count down is because it has i-- instead of ++i in the past. also i stops at 0 is because it has i<=0 command in forloop setup, when this coindition reached, the loop will end.

Q9 the output will be like:
100
90
80
70
60
50
40
30
20
10
0

it count down by 10 is because it have --10 command

Q11 this is generate:
0	1
10	11
20	21
30	31
40	41
50	51
60	61
70	71
80	81
90	91

The second one is 1 greater than the previrous is because of the i+1 statment in cout command.

Q12
    for (int i {0}; i <= 90; i += 10) {
        cout << i << "\t" << i * 2 << "\n";
    }



Extra Credit:
    for (int i {0}; i <= 90; i += 10) {
        cout << i << "\t" << i * 2 << "\n";
    }


For if statment:
Q1
for (int i {0}; i < 10; ++i) {
        if (i % 2 == 0) {
            cout << i << " is even." << "\n";
        } else {
            cout << i << " is odd." << "\n";
        }
    }

Q2
for (int year {2000}; year <= 2028; ++year) {
        if (year % 4 == 0) {
            cout << year << " is a presidential election year." << "\n";
        } else if (year % 4 == 2) {
            cout << year << " is a midterm election year." << "\n";
        } else {
            cout << year << " is a local election year." << "\n";
        }
    }

Q3
    time_t t {time(nullptr)};          
    tm *p {localtime(&t)};             
    int currentYear {p->tm_year + 1900}; 

    int year; 

    if (year < currentYear) {
        cout << year << " was a good year.\n";
    } else if (year == currentYear) {
        cout << year << " is a good year.\n";
    } else {
        cout << year << " will be a good year.\n";
    }


Q4The two pieces of code will not produce the same output
	the first code uses multiple if statments, so it can print more than one messages
	the second code uses if/else if/else, so it will print only one message

	for example when time is 12pm or 6pm,
	the first code might have more than one message
	the second code will only print one message