/* Remedial 

1. for (int i {0}; i < 10; ++i) {
	cout << i << "\n";
}

Ans: It iterates 10 times. The first value of i is 0. The second value of i is 1. The last value of i is 9.
0
1
2
3
4
5
6
7
8
9

2. for (int i{0}; i < 10; ++i) {
	cout << i << "\n\n";
}

Ans"
0

1

2

3

4

5

6

7

8

9

10

3. for (int i {0}; i < 10; ++i) {
	cout << i << "  ";

}
   
   cout <<"\n";

Ans:
0 1 2 3 4 5 6 7 8 9


4. for (int i {0}; i < 10; ++i) {
	cout << i << "\n";
}

Ans: 
Make i start at 1 instead of 0.

for (int i {1}; i < 10; ++i) {
    cout << i << "\n";
}

Make it start at 5 instead of 1

for (int i {5}; i < 10; ++1) {
   cout << i << "\n";
}

5. What does the following loop output?
   Why doe it now count up to 10 instead of stoping at 9?

for (int i {0}; i <= 10; ++i) {
	cout << 1 << "\n";
}

Ans:

0
1
2
3
4
5
6
7
8
9
10 

It now counts up to 10 because of the "<=", so now i also equals 10.

6. Make a loop that put integers from 10 to 20 inclusive, in increasing order, one after another on the same line, separated by spaces.

for (int i {10} i <= 20; ++i){
   cout << i << " ";
}

7. What does the following loop output? What does += do?  

for (int i {10}; i <= 100; i += 10) { 
	cout << i << "\n";
}

Ans:
10
20
30
40
50
60
70
80
90
100

+= 10 increase increases the integer by 10, adding 10 to the previous iterate each time until it reaches 100. 

8. Write a loop that outputs 

2
4
6
8

for (int i {2}; i <= 8; i += 2) {
	cout << i << "\n";
}

9. What does the following loop output? Why does it count down? Why does it stop at 0?

for( int i {10}; i >= 0; --i) { 
	cout << i << "\n";
}