#include <iostream>
#include <chrono>
#include <ctime>
#include "date.h"
using namespace std;

const int date::length[] {
	 0,   //dummy, so that January will have subscript 1
	31,   //January
	28,   //February.  Pretend there are no leap years.
	31,   //March
	30,   //April
	31,   //May
	30,   //June
	31,   //July
	31,   //August
	30,   //September
	31,   //October
	30,   //November
	31    //December
};

date::date(int m, int d, int y)
    : day(365 * y + d - 1)
{
    for (int month {1}; month < m; ++month) {
        day += length[month];
    }
}

date::date()    //today's date
{
    const auto now {chrono::system_clock::now()};
    const time_t t {chrono::system_clock::to_time_t(now)};
    const tm *const p {localtime(&t)};

    day = 365 * (p->tm_year + 1900) + p->tm_yday;
}

void date::print() const
{
    const int year {day / 365};
    int dayOfYear  {day % 365 + 1};

    int month {1};
    for (; dayOfYear > date::length[month]; ++month) {
        dayOfYear -= date::length[month];
    }

    cout << month << "/" << dayOfYear << "/" << year;
}

//Added operators
// equality
bool operator==(const date& a, const date& b)
{
    return a.day == b.day;
}

// less than
bool operator<(const date& a, const date& b)
{
    return a.day < b.day;
}

// +=  
date& date::operator+=(int n)
{
    day += n;
    return *this;
}

// prefix 
date& date::operator++()
{
    *this += 1;   
    return *this;
}

// postfix
date date::operator++(int)
{
    const date old {*this}; 
    ++(*this);              
    return old;
}